Integrand size = 38, antiderivative size = 147 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=-\frac {a^2 c}{2 x^2}-\frac {a^2 d}{x}+a (2 b c+a f) x+\frac {1}{2} a (2 b d+a g) x^2+\frac {2}{3} a b e x^3+\frac {1}{4} b (b c+2 a f) x^4+\frac {1}{5} b (b d+2 a g) x^5+\frac {1}{6} b^2 e x^6+\frac {1}{7} b^2 f x^7+\frac {1}{8} b^2 g x^8+\frac {h \left (a+b x^3\right )^3}{9 b}+a^2 e \log (x) \]
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Time = 0.09 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {1597, 1834} \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=-\frac {a^2 c}{2 x^2}-\frac {a^2 d}{x}+a^2 e \log (x)+\frac {1}{4} b x^4 (2 a f+b c)+a x (a f+2 b c)+\frac {1}{5} b x^5 (2 a g+b d)+\frac {1}{2} a x^2 (a g+2 b d)+\frac {2}{3} a b e x^3+\frac {h \left (a+b x^3\right )^3}{9 b}+\frac {1}{6} b^2 e x^6+\frac {1}{7} b^2 f x^7+\frac {1}{8} b^2 g x^8 \]
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Rule 1597
Rule 1834
Rubi steps \begin{align*} \text {integral}& = \frac {h \left (a+b x^3\right )^3}{9 b}+\int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4\right )}{x^3} \, dx \\ & = \frac {h \left (a+b x^3\right )^3}{9 b}+\int \left (a (2 b c+a f)+\frac {a^2 c}{x^3}+\frac {a^2 d}{x^2}+\frac {a^2 e}{x}+a (2 b d+a g) x+2 a b e x^2+b (b c+2 a f) x^3+b (b d+2 a g) x^4+b^2 e x^5+b^2 f x^6+b^2 g x^7\right ) \, dx \\ & = -\frac {a^2 c}{2 x^2}-\frac {a^2 d}{x}+a (2 b c+a f) x+\frac {1}{2} a (2 b d+a g) x^2+\frac {2}{3} a b e x^3+\frac {1}{4} b (b c+2 a f) x^4+\frac {1}{5} b (b d+2 a g) x^5+\frac {1}{6} b^2 e x^6+\frac {1}{7} b^2 f x^7+\frac {1}{8} b^2 g x^8+\frac {h \left (a+b x^3\right )^3}{9 b}+a^2 e \log (x) \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.86 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=\frac {a^2 \left (-3 c-6 d x+x^3 \left (6 f+3 g x+2 h x^2\right )\right )}{6 x^2}+\frac {1}{30} a b x \left (60 c+x \left (30 d+x \left (20 e+15 f x+12 g x^2+10 h x^3\right )\right )\right )+\frac {b^2 x^4 (630 c+x (504 d+5 x (84 e+x (72 f+7 x (9 g+8 h x)))))}{2520}+a^2 e \log (x) \]
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Time = 1.49 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.01
method | result | size |
norman | \(\frac {\left (\frac {1}{2} a^{2} g +a b d \right ) x^{4}+\left (\frac {1}{3} a^{2} h +\frac {2}{3} a e b \right ) x^{5}+\left (\frac {2}{5} a b g +\frac {1}{5} b^{2} d \right ) x^{7}+\left (\frac {1}{3} a b h +\frac {1}{6} b^{2} e \right ) x^{8}+\left (\frac {1}{2} a f b +\frac {1}{4} b^{2} c \right ) x^{6}+\left (a^{2} f +2 a b c \right ) x^{3}-\frac {a^{2} c}{2}-a^{2} d x +\frac {b^{2} f \,x^{9}}{7}+\frac {b^{2} g \,x^{10}}{8}+\frac {b^{2} h \,x^{11}}{9}}{x^{2}}+a^{2} e \ln \left (x \right )\) | \(148\) |
default | \(\frac {b^{2} h \,x^{9}}{9}+\frac {b^{2} g \,x^{8}}{8}+\frac {b^{2} f \,x^{7}}{7}+\frac {a b h \,x^{6}}{3}+\frac {b^{2} e \,x^{6}}{6}+\frac {2 a b g \,x^{5}}{5}+\frac {b^{2} d \,x^{5}}{5}+\frac {a b f \,x^{4}}{2}+\frac {b^{2} c \,x^{4}}{4}+\frac {a^{2} h \,x^{3}}{3}+\frac {2 a b e \,x^{3}}{3}+\frac {a^{2} g \,x^{2}}{2}+x^{2} a b d +a^{2} f x +2 a b c x +a^{2} e \ln \left (x \right )-\frac {a^{2} d}{x}-\frac {a^{2} c}{2 x^{2}}\) | \(150\) |
risch | \(\frac {b^{2} h \,x^{9}}{9}+\frac {b^{2} g \,x^{8}}{8}+\frac {b^{2} f \,x^{7}}{7}+\frac {a b h \,x^{6}}{3}+\frac {b^{2} e \,x^{6}}{6}+\frac {2 a b g \,x^{5}}{5}+\frac {b^{2} d \,x^{5}}{5}+\frac {a b f \,x^{4}}{2}+\frac {b^{2} c \,x^{4}}{4}+\frac {a^{2} h \,x^{3}}{3}+\frac {2 a b e \,x^{3}}{3}+\frac {a^{2} g \,x^{2}}{2}+x^{2} a b d +a^{2} f x +2 a b c x +\frac {-a^{2} d x -\frac {1}{2} a^{2} c}{x^{2}}+a^{2} e \ln \left (x \right )\) | \(150\) |
parallelrisch | \(\frac {280 b^{2} h \,x^{11}+315 b^{2} g \,x^{10}+360 b^{2} f \,x^{9}+840 a b h \,x^{8}+420 b^{2} e \,x^{8}+1008 a b g \,x^{7}+504 b^{2} d \,x^{7}+1260 a b f \,x^{6}+630 b^{2} c \,x^{6}+840 a^{2} h \,x^{5}+1680 a b e \,x^{5}+1260 a^{2} g \,x^{4}+2520 a b d \,x^{4}+2520 a^{2} e \ln \left (x \right ) x^{2}+2520 a^{2} f \,x^{3}+5040 a b c \,x^{3}-2520 a^{2} d x -1260 a^{2} c}{2520 x^{2}}\) | \(160\) |
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Time = 0.30 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.04 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=\frac {280 \, b^{2} h x^{11} + 315 \, b^{2} g x^{10} + 360 \, b^{2} f x^{9} + 420 \, {\left (b^{2} e + 2 \, a b h\right )} x^{8} + 504 \, {\left (b^{2} d + 2 \, a b g\right )} x^{7} + 630 \, {\left (b^{2} c + 2 \, a b f\right )} x^{6} + 840 \, {\left (2 \, a b e + a^{2} h\right )} x^{5} + 2520 \, a^{2} e x^{2} \log \left (x\right ) + 1260 \, {\left (2 \, a b d + a^{2} g\right )} x^{4} - 2520 \, a^{2} d x + 2520 \, {\left (2 \, a b c + a^{2} f\right )} x^{3} - 1260 \, a^{2} c}{2520 \, x^{2}} \]
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Time = 0.19 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.07 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=a^{2} e \log {\left (x \right )} + \frac {b^{2} f x^{7}}{7} + \frac {b^{2} g x^{8}}{8} + \frac {b^{2} h x^{9}}{9} + x^{6} \left (\frac {a b h}{3} + \frac {b^{2} e}{6}\right ) + x^{5} \cdot \left (\frac {2 a b g}{5} + \frac {b^{2} d}{5}\right ) + x^{4} \left (\frac {a b f}{2} + \frac {b^{2} c}{4}\right ) + x^{3} \left (\frac {a^{2} h}{3} + \frac {2 a b e}{3}\right ) + x^{2} \left (\frac {a^{2} g}{2} + a b d\right ) + x \left (a^{2} f + 2 a b c\right ) + \frac {- a^{2} c - 2 a^{2} d x}{2 x^{2}} \]
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Time = 0.20 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.99 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=\frac {1}{9} \, b^{2} h x^{9} + \frac {1}{8} \, b^{2} g x^{8} + \frac {1}{7} \, b^{2} f x^{7} + \frac {1}{6} \, {\left (b^{2} e + 2 \, a b h\right )} x^{6} + \frac {1}{5} \, {\left (b^{2} d + 2 \, a b g\right )} x^{5} + \frac {1}{4} \, {\left (b^{2} c + 2 \, a b f\right )} x^{4} + \frac {1}{3} \, {\left (2 \, a b e + a^{2} h\right )} x^{3} + a^{2} e \log \left (x\right ) + \frac {1}{2} \, {\left (2 \, a b d + a^{2} g\right )} x^{2} + {\left (2 \, a b c + a^{2} f\right )} x - \frac {2 \, a^{2} d x + a^{2} c}{2 \, x^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.02 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=\frac {1}{9} \, b^{2} h x^{9} + \frac {1}{8} \, b^{2} g x^{8} + \frac {1}{7} \, b^{2} f x^{7} + \frac {1}{6} \, b^{2} e x^{6} + \frac {1}{3} \, a b h x^{6} + \frac {1}{5} \, b^{2} d x^{5} + \frac {2}{5} \, a b g x^{5} + \frac {1}{4} \, b^{2} c x^{4} + \frac {1}{2} \, a b f x^{4} + \frac {2}{3} \, a b e x^{3} + \frac {1}{3} \, a^{2} h x^{3} + a b d x^{2} + \frac {1}{2} \, a^{2} g x^{2} + 2 \, a b c x + a^{2} f x + a^{2} e \log \left ({\left | x \right |}\right ) - \frac {2 \, a^{2} d x + a^{2} c}{2 \, x^{2}} \]
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Time = 9.83 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.99 \[ \int \frac {\left (a+b x^3\right )^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{x^3} \, dx=x\,\left (f\,a^2+2\,b\,c\,a\right )-\frac {\frac {a^2\,c}{2}+a^2\,d\,x}{x^2}+x^4\,\left (\frac {c\,b^2}{4}+\frac {a\,f\,b}{2}\right )+x^2\,\left (\frac {g\,a^2}{2}+b\,d\,a\right )+x^5\,\left (\frac {d\,b^2}{5}+\frac {2\,a\,g\,b}{5}\right )+x^3\,\left (\frac {h\,a^2}{3}+\frac {2\,b\,e\,a}{3}\right )+x^6\,\left (\frac {e\,b^2}{6}+\frac {a\,h\,b}{3}\right )+\frac {b^2\,f\,x^7}{7}+\frac {b^2\,g\,x^8}{8}+\frac {b^2\,h\,x^9}{9}+a^2\,e\,\ln \left (x\right ) \]
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